DSAndOS/DSBookCode/BookCode/第6章/6.1.cpp

//算法6.1　采用邻接矩阵表示法创建无向网

#include <iostream>
using namespace std;

#define MaxInt 32767                    	//表示极大值，即∞
#define MVNum 100                       	//最大顶点数
#define OK 1	
 						
typedef char VerTexType;              		//假设顶点的数据类型为字符型 
typedef int ArcType;                  		//假设边的权值类型为整型 

//- - - - -图的邻接矩阵存储表示- - - - -
typedef struct{ 
	VerTexType vexs[MVNum];            		//顶点表 
	ArcType arcs[MVNum][MVNum];      		//邻接矩阵 
	int vexnum,arcnum;                		//图的当前点数和边数 
}AMGraph;

int LocateVex(AMGraph G , VerTexType v){
	//确定点v在G中的位置
	for(int i = 0; i < G.vexnum; ++i)
		if(G.vexs[i] == v)
			return i;
   return -1;
}//LocateVex

int CreateUDN(AMGraph &G){ 
    //采用邻接矩阵表示法，创建无向网G 
	int i , j , k;
	cout <<"请输入总顶点数，总边数，以空格隔开：";
    cin >> G.vexnum >> G.arcnum;							//输入总顶点数，总边数
	cout << endl;

	cout << "输入点的名称，如a" << endl;

    for(i = 0; i < G.vexnum; ++i){   
		cout << "请输入第" << (i+1) << "个点的名称:";
		cin >> G.vexs[i];                        			//依次输入点的信息 
	}
	cout << endl;
    for(i = 0; i < G.vexnum; ++i)                			//初始化邻接矩阵，边的权值均置为极大值MaxInt 
		for(j = 0; j < G.vexnum; ++j)   
			G.arcs[i][j] = MaxInt;  
	cout << "输入边依附的顶点及权值，如 a b 5" << endl;
	for(k = 0; k < G.arcnum;++k){							//构造邻接矩阵 
		VerTexType v1 , v2;
		ArcType w;
		cout << "请输入第" << (k + 1) << "条边依附的顶点及权值:";
		cin >> v1 >> v2 >> w;								//输入一条边依附的顶点及权值
		i = LocateVex(G, v1);  j = LocateVex(G, v2);		//确定v1和v2在G中的位置，即顶点数组的下标 
		G.arcs[i][j] = w;									//边<v1, v2>的权值置为w 
		G.arcs[j][i] = G.arcs[i][j];						//置<v1, v2>的对称边<v2, v1>的权值为w 
	}//for	
	return OK; 
}//CreateUDN 

int main(){
	cout << "************算法6.1　采用邻接矩阵表示法创建无向网**************" << endl << endl;
	AMGraph G;     int i , j;
	CreateUDN(G);
	
	cout <<endl;
	cout << "*****邻接矩阵表示法创建的无向网*****" << endl;
	
	for(i = 0 ; i < G.vexnum ; ++i){
		for(j = 0; j < G.vexnum; ++j){
			if(j != G.vexnum - 1){
				if(G.arcs[i][j] != MaxInt)
					cout << G.arcs[i][j] << "\t";
				else
					cout << "∞" << "\t";
			}
			else{
				if(G.arcs[i][j] != MaxInt)
					cout << G.arcs[i][j] <<endl;
				else
					cout << "∞" <<endl;
			}
		}
	}//for
	cout <<endl;
	return 0;
}//main